Question

If the roots of the equation mx2 - 3mx+9 = 0 are real and equal, find the
value of m.​

Answer 1

Answer:

comparing mx²-3mx+9 = 0 with ax²+bx+c =0

a= m ,b = -3 ,c=9

b²-4ac

= (-3)²- 4×m×9

= 9 -36m

but roots of this equation are real and equal

b²-4ac =0

9-36m=0

-36m =-9

-m= -9 /36

-m = -1/4

m=1/4

Answer 2

Answer:

Answer:

comparing mx²-3mx+9 = 0 with ax²+bx+c =0

a= m ,b = -3 ,c=9

b²-4ac

= (-3)²- 4×m×9

= 9 -36m

but roots of this equation are real and equal

b²-4ac =0

9-36m=0

-36m =-9

-m= -9 /36

-m = -1/4

m=1/4

Step-by-step explanation:

Hope this answer will help you.