If the roots of the equation mx2 - 3mx+9 = 0 are real and equal, find the
value of m.
Answers
Answered by
3
Answer:
comparing mx²-3mx+9 = 0 with ax²+bx+c =0
a= m ,b = -3 ,c=9
b²-4ac
= (-3)²- 4×m×9
= 9 -36m
but roots of this equation are real and equal
b²-4ac =0
9-36m=0
-36m =-9
-m= -9 /36
-m = -1/4
m=1/4
Answered by
3
Answer:
Answer:
comparing mx²-3mx+9 = 0 with ax²+bx+c =0
a= m ,b = -3 ,c=9
b²-4ac
= (-3)²- 4×m×9
= 9 -36m
but roots of this equation are real and equal
b²-4ac =0
9-36m=0
-36m =-9
-m= -9 /36
-m = -1/4
m=1/4
Step-by-step explanation:
Hope this answer will help you.
Similar questions