Question

If the roots of the equation mx² – 3mx +9=0 are real and equal, find thevalue of m.
Answer : m = 4​

Answer 1

Answer:

discriminant,D=b²-4ac

here,a=m,b= -3m,c=9

D=9m²-36m

given that roots are real and equal.

so D=0

9m²-36m=0

9m²=36m

m=4.

Answer 2

Answer:

4

Step-by-step explanation:

mx² – 3mx +9=0  

=>  roots are real and equal​ => b² - 4ac = 0

a =m, b= -3m,  c = 9

from formula, 9m²- 4(m)9 = 0

m - 4 = 0  

m = 4

Hope it helps

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