If the roots of the equation q²x² + p²x + r² = 0 are the squares of the roots of the equation qx² + p²x + r² = 0 then p,q,r are in
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Equation px
2
+2qx+r=0 and qx
2
−2
pr
x+q=0 have real roots, then
b
2
−4ac≥0 for both equations
From first
4q
2
−4pr≥0⇒q
2
≥pr ...............(1)
and from second
4(pr)−4q
2
≥0 (for real root)
⇒pr≥q
2
...............(2)
From (1) and (2), we get result q
2
=pr
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