If the roots of the equation
are in the ratio 2:3, then which is correct
Answers
Answered by
50
Given Equation is 3ax^2 + 2bx + c = 0.
Here a = 3a, b = 2b, c = c.
Let 2x,3x be the roots of the equation.
Here,
(i)
Sum of roots = -b/a
= > 2x + 3x = -2b/3a
= > 5x = -2b/3a.
= > x = -2b/15a
(ii)
Product of roots = c/a
= > (2x)(3x) = c/3a
= > 6x^2 = c/3a
= > 6(-2b/15a)^2 = c/3a
= > 6(-4b^2/225a^2) = c/3a
= > (4b^2/225a^2) = c/18a
= > 18a(4b^2) = 225a^2c
= > 18 * 4b^2 = 225ac
= > 72b^2 = 9 * 25ac
= > 9 * 8b^2 = 9 * 25ac
= > 8b^2 = 25ac.
The answer is Option (4). - 8b^2 = 25ac
Hope this helps!
Here a = 3a, b = 2b, c = c.
Let 2x,3x be the roots of the equation.
Here,
(i)
Sum of roots = -b/a
= > 2x + 3x = -2b/3a
= > 5x = -2b/3a.
= > x = -2b/15a
(ii)
Product of roots = c/a
= > (2x)(3x) = c/3a
= > 6x^2 = c/3a
= > 6(-2b/15a)^2 = c/3a
= > 6(-4b^2/225a^2) = c/3a
= > (4b^2/225a^2) = c/18a
= > 18a(4b^2) = 225a^2c
= > 18 * 4b^2 = 225ac
= > 72b^2 = 9 * 25ac
= > 9 * 8b^2 = 9 * 25ac
= > 8b^2 = 25ac.
The answer is Option (4). - 8b^2 = 25ac
Hope this helps!
Similar questions