If the roots of the equation x²+px+7=0 are denoted by α and β, and α²+β²=22 , find the possible values of p
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p = +6
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Answer:
The given eqn is,
x^2+px+7=0
sum of the roots = - b/ a
product of the roots = c/a
here a = 1 , b = p , c = 7
sum of the roots (alpha + beta ) = - p
product of the roots (alpha× beta ) = 7
( alpha + beta )^2 = p^2
Also given :
alpha^2 + beta^2 =22
Consider
( alpha + beta ) ^2 = p ^2
alpha^2 + 2 × ( alpha × beta ) + beta ^2 = p^2
alpha^2 + beta ^2 + 2× ( alpha × beta) = p^2
22+ 2×7 = p^2
22+14 = p^2
36 = p^2
p = + or - 6
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