Math, asked by shreyanithin2007, 7 months ago

if the roots of the equation x2+px+q=0x2+px+q=0
differ by 1 then​

Answers

Answered by ng2076351
3

Step-by-step explanation:

Given equation x^2+px+q=0

Let the roots be α,β

α+β=−p and αβ=q

Now, (α−β)^2=(α−β)^2 −4αβ

⇒(α−β)^2=p^2 −4q

Given ∣α−β| =1

(α−β)^2=1

p^2 −4q=1

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