if the roots of the equation x2+px+q=0x2+px+q=0
differ by 1 then
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Step-by-step explanation:
Given equation x^2+px+q=0
Let the roots be α,β
α+β=−p and αβ=q
Now, (α−β)^2=(α−β)^2 −4αβ
⇒(α−β)^2=p^2 −4q
Given ∣α−β| =1
(α−β)^2=1
p^2 −4q=1
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