Question

If the roots of the quadratic eqn (x-a)(x-b)-k=0 are c & d, then, find the roots of quadratic eqn (x-c)(x-d)+k=0​

Answer 1

ANSWER-

$\huge{\boxed{\sf{TWO\:ROOTS\:ARE=a,b}}}$

Step-by-step explanation:

$\huge{\boxed{\sf{SOLUTION-}}}$

FORMULA USE IN THIS QUESTIONS:

$\huge{\boxed{\sf{a{x}^{2}+bx+c=a(x-\alpha)(x-\beta)}}}$

(x-a)(x-b)-k=0

SO THE GIVEN ROOTS OF THIS QUADRATIC IS = c & d

#(x-a)(x-b)-k=(x-c)(x-d)

=)(x-c)(x-d)+k=(x-a)(x-b)

$\huge{\boxed{\sf{=)(x-c)(x-d)+k=0\:\:roots=a\:and\:b}}}$

#ROOTS OF (x-c)(x-d)+k=ab✔✔