if the roots of the quadratic equation 2kx2+(2a+b)x-ab=0 are (-2,a) the value of k is
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Step-by-step explanation:
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Step-by-step explanation:
P(a) = 2ka^2 + (2a+b) a - ab
2ka^2 + 2a^2 + ab - ab= 0
2a^2(k + 1) = 0
k + 1 = 0
k = - 1
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