if the roots of the quadratic equation 2x2+8x+k=0 are equal them find the value of k.
Answers
Answered by
2
Answer:
8
Step-by-step explanation:
Let each roots is 'a'.
In equations written in form of ax² + bx + c = 0,
-b/a is sum of roots ; c/a is product of roots.
Here, as both roots are equal:
= > sum = -(8/2)
= > a + a = - 4
= > 2a = - 4 → a = - 2
Whereas,
= > product = k/2
= > a*a = k/2
= > (-2)(-2) = k/2
= > 4 = k/2
= > 8 = k
Answered by
25
ANSWER
2x²+8x+k = 0
Here, a=2, b=8 & c=k
As roots are real & equal, therefore discriminant is equal to 0.
D = 0
D = 0b² -4ac = 0
D = 0b² -4ac = 0b² = 4ac
8² = 4×2×k
64 = 8k
k = 64/8
k = 8
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