If the roots of the quadratic equation 9x² + kx + k = 8 are real and equal, what is the value of k?
how are you all
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1
Answer
9x
2
+8kx+16=0
Compare given equation with the general form of quadratic equation, which ax
2
+bx+c=0
a=9,b=8k,c=16
Find D:
D=b
2
−4ac
=(8k)
2
−4×9×16
=64k
2
−576
Roots of given equation are equal (given)
So, D=0
64k
2
−576=0
64k
2
=576
k
2
=9
k=±3
Answer k=3,k=−3
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Answer:
If the roots of the quadratic equation 9x² + kx + k = 8 are real and equal, what is the value of k? how are you all · Answer · Answer · Still have ...
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