History, asked by xxsanshkiritixx, 13 hours ago

If the roots of the quadratic equation 9x² + kx + k = 8 are real and equal, what is the value of k?

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Answers

Answered by AshMaXSiRa
1

Answer

9x

2

+8kx+16=0

Compare given equation with the general form of quadratic equation, which ax

2

+bx+c=0

a=9,b=8k,c=16

Find D:

D=b

2

−4ac

=(8k)

2

−4×9×16

=64k

2

−576

Roots of given equation are equal (given)

So, D=0

64k

2

−576=0

64k

2

=576

k

2

=9

k=±3

Answer k=3,k=−3

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Answered by s14975apratibha07847
1

Answer:

If the roots of the quadratic equation 9x² + kx + k = 8 are real and equal, what is the value of k? how are you all · Answer · Answer · Still have ...

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