Question

If the roots of the Quadratic Equation (a-b)x^2 + (b-c)x +(c-a) =0 are equal, then prove that 2a= b+c.

Answer 1

do b^2 -4ac
u will get the ans

Answer 2

Heya

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For equal roots Descrimnant = 0

=>

Descrimnant = (b - c)² - 4 (a - b) × (c- a)

=>

(b - c)² - 4 (a - b) × (c - a) = 0

=>

b² + c² - 2bc - 4ac + 4a² + 4bc - 4ab = 0

=>

b² + c² + 2bc = - 4a² + 4ab + 4ac

=>

( b + c )² = 4a { - a + b + c }