If the roots of the quadratic equation (a-b)x²+(b-c)x+(c-a) are equal than prove that 2a=b+c
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D=0
(b-c)^2 - 4(a-b)(c-a) = 0
b^2 + c^2 -2bc - 4(ac - a^2 - bc + ab ) = 0
b^2 + c^2 -2bc +4bc -4ac + 4a^2 - 4ab = 0
(2a - b -c )^2 = 0
2a - b - c = 0
2a = b+ c
Step-by-step explanation:
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