Question

If the roots of the quadratic equation kx +27x+20=0 where k#0 are in the ratio 4:5. then find the posible value of 'k (a) 8 (6) 6 (c) 4 (d) 9​

Answer 1

Answer:

kx2−5x+k=0

Here a=k,b=−5,c=k

Given that the equation has equa roots.

Therefore,

D=0

b2−4ac=0

(−5)−4(k)(k)=0

25−4k2=0

⇒4k2=25

⇒k=±425=±25

Hence the value of k is ±25.