If the roots of the quadratic equation p(q-r)x^3 + q(r-p)x + r(p-q) = 0 are equal, show that : 1/p + 1/r = 2/q
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Use the formula of discriminant..
d=b^2-4ac=0
Here d=0 because the roots are equal hence real and repeating..
Substitute in the formula and get answer...
d=b^2-4ac=0
Here d=0 because the roots are equal hence real and repeating..
Substitute in the formula and get answer...
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