if the roots of the quadratic equation x^2+MX+n=0 are tan 30 and tan 15, respectively, then find 2+n-m...
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Answer:
Given x
2
+px+q=0
From the given equation tan30
∘
+tan15
∘
=−p and tan30
∘
tan15
∘
=q
Now
tan(30
∘
+15
∘
)=
1−tan30
∘
tan15
∘
tan30
∘
+tan15
∘
⇒tan(45
∘
)=−
1−q
p
⇒1=−
1−q
p
⇒1−q=−p⇒q−p=1
⇒2+q−p=3
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