Question

if the roots of the quadratic equation X square - 3 x + 9 = 0 are equal then the value of p is ​

Answer 1

One way to solve the quadratic equation x2 = 9 is to subtract 9 from both sides to get one side equal to 0: x2 – 9 = 0. The expression on the left can be factored: (x + 3)(x – 3) = 0. Using the zero factor property, you know this means x + 3 = 0 or x – 3 = 0, so x = −3 or 3 .

Answer 2

Answer:

• $x^{2} -px+9=0$

GIVEN:

• The given quadratic equation has equal roots.

⇒D = b² - 4ac = 0

SOLUTION:

• a = 1, b = p, c = 9

0 = p² - 4 (1 x 9)

0 = p² - 36

p² = 36

p = √36

p = ±6

∴The Values of p are +6 or -6