Math, asked by 044011538, 1 month ago

if the roots of the quadratic equation x²+2kx+4=0 are equal then the value of K is








Answers

Answered by saritamahala99
1

Step-by-step explanation:

dekh yahan k ki value ±2 hogi

soln.

roots are equal b²-4ac=0

b= 2k ,a=1,c=4 put the values

4k²-16=0

4k²=16

k²=4

k=±2.

hope you got it

Answered by AestheticSoul
3

Required Answer :

The value of k = 2 or - 2

Given :

The roots of the following quadratic equation are equal :

= x² + 2kx + 4 = 0

To find :

The value of k

Solution :

Here, we are given that the roots of the given quadratic equation are equal. So, b² - 4ac will be equal to 0. To find the value of k we will use the discriminant formula.

→ x² + 2kx + 4 = 0

→ b² - 4ac = 0 (Because roots are equal.)

we have,

• a = 1

• b = 2k

• c = 4

Substituting the given values :

→ (2k)² - 4(1)(4) = 0

→ 4k² - 16 = 0

→ 4k² = 16

→ k² = 16/4

→ k² = 4

→ Taking square root on both the sides :

→ k = √4

→ k = √(2 × 2)

→ k = ± 2

Therefore,

  • The value of k = 2 or - 2

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Know more :

→ b² - 4ac > 0

Roots are real and unequal.

→ b² - 4ac < 0

Roots are imaginary.

→ b² - 4ac = 0

Roots are real and equal.

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