if the roots of the quadratic equation x²+2kx+4=0 are equal then the value of K is
Answers
Step-by-step explanation:
dekh yahan k ki value ±2 hogi
soln.
roots are equal b²-4ac=0
b= 2k ,a=1,c=4 put the values
4k²-16=0
4k²=16
k²=4
k=±2.
hope you got it
Required Answer :
The value of k = 2 or - 2
Given :
The roots of the following quadratic equation are equal :
= x² + 2kx + 4 = 0
To find :
The value of k
Solution :
Here, we are given that the roots of the given quadratic equation are equal. So, b² - 4ac will be equal to 0. To find the value of k we will use the discriminant formula.
→ x² + 2kx + 4 = 0
→ b² - 4ac = 0 (Because roots are equal.)
we have,
• a = 1
• b = 2k
• c = 4
Substituting the given values :
→ (2k)² - 4(1)(4) = 0
→ 4k² - 16 = 0
→ 4k² = 16
→ k² = 16/4
→ k² = 4
→ Taking square root on both the sides :
→ k = √4
→ k = √(2 × 2)
→ k = ± 2
Therefore,
- The value of k = 2 or - 2
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Know more :
→ b² - 4ac > 0
Roots are real and unequal.
→ b² - 4ac < 0
Roots are imaginary.
→ b² - 4ac = 0
Roots are real and equal.