if the roots of the quadratic equation x2-4x-logN,then what is the minimum value of N?
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Answer:
Ask this in the Math section please.
Explanation:
Answered by
0
Answer:
roots are real so
D>=0
minimum value,
D=0
so,b^2- 4ac=0
(-4) ^2-4*1*(-logN) =0
16+4logN=0
16=-4logN
-4=logN
N=10^-4
N=.0001
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