Question

If the roots of the quadratic polynomial p(x)=x²+(a+1)x+b is 2 and -3 then find the values of a and b

Answer 1

Step-by-step explanation:

zeros are 2 and -3

x = 2 x - 2 = 0

x = -3 x + 3 = 0

$(x - 2)(x + 3) = 0 \\ {x}^{2} + 3x - 2x - 6 = 0 \\ {x}^{2} + x - 6 = 0$

substitute the terms we get in the equation

a + 1 = 1

a = 1 - 1 = 0

b = -6

hope you get your answer