Question

If the roots of this equation has real and equal roots then find the value of k ... ( x²-kx+k=0 )​

Answer 1

Answer:

k=0,4

Step-by-step explanation:

The roots of the equation are real and equal which means

b^2(B square)-4ac=0

a=1,b=-k,c=k

k^2-4k =0

k(k-4)=0

k=0 or k=4

Answer 2

$\huge\mathcal\fcolorbox{red}{black}{ANSWER}$

x²+kx+k=0 has only one solution.

∴ The discriminant b² −4ac=0

∴k²−4k=0

⇒k(k−4)=0

∴k=0 or k=4

So for k=0 or k=4 the equation x²

+4x+4=0 has only one solution

$\huge\mathcal\fcolorbox{red}{black}{ANSWERED BY}$

$\huge\mathcal\fcolorbox{red}{black}{@FFdevansh}$