Question

. If the roots of x^2 + 4x + k=0 are real, then the value(s) of k is (are)

Answer 1

Answer:

k > 4

Step-by-step explanation:

if the roots of x²+4x+k are real then,

b²-4ac > 0

(4)²-4(1)(k) > 0

16-4k > 0

-4k > -16

k > 16/4

k > 4

hope this helps you