Question

If the roots of x^4 -8x^3+bx+16=0 are postive real numbers then a is ​

Answer 1

Answer:

The roots of the equation x4 -8x3 + ax2 - bx + 16

= 0, are positive, if(A) a = 24(B) a = 12(C) b = = 8(D)b = 32. ... If A : B: C=2:3:4, then the ratio ... If

a,b,c are positive real numbers, then the number of positive.