Question

if the roots of x square + kx + K =0 are real and equal what is the value of k

Answer 1

Answer:

k=4

Step-by-step explanation:

If the equation has real and equal roots, then

D = 0

=> b² - 4ac = 0

a=1 , b = k and c =k

(k)²-4(1)(k)=0

k²-4k=0

k(k-4) =0

k=0

and

k-4=0

k=4

Answer 2

Answer:

4

Step-by-step explanation:

x²+kx+k

If the roots are real and equal then D=0

Therefore,

b²-4ac=0

So, k²-4k=0

k²=4k

k=4