if the roots of x²-3x+2=0 are alpha and beta then the equation of roots alpha+2, beta+2
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Step-by-step explanation:
α+β=3;αβ=2
S=(α+2+β+2)
=(α+β+4)
=(3+4)
= 7
P=(α+2)(β+2)
=αβ+2α+2β+4
=2+2(α+β) +4
=2+2(3) +4
= 12
∴ Equation whose roots are (α+2),(β+2) is
x² - Sx + P = 0
x² - 7x + 12 = 0
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