Question

If the roots of x2 + 8x + 5=0 exceed k then​

Answer 1

$Given \: quadratic \: equation :\\x^{2} + 8x + 5 = 0$

$Compare \: this \: with \: ax^{2} + bx + c = 0 \:, \\we \:get$

$a = 1 , b = 8 , c = 5$

$Discreminant (D) = b^{2} - 4ac \\= 8^{2} - 4\times 1 \times 5 \\= 64 - 20 \\= 44$

Using Quadratic Formula:

$x = \frac{-b±\sqrt{D}}{2a}$

$=\frac{-8±\sqrt{44}}{2}$

$= \frac{2(-4±\sqrt{11})}{2}$

$=-4±\sqrt{11}$

Therefore.,

$\red { Roots }\green {= -4±\sqrt{11} }$

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