Math, asked by tanmaybhere100, 1 year ago

If the roots of x² + kx + k = 0 are real and equal, what is the value of k?
(A) 0
(B) 4
(C) 0 or 4
(D) 2

Answers

Answered by brunoconti
8

Answer:

Step-by-step explanation:

Roots are equal then DELTA = 0.Then

k^2 - 4k = 0, then k(k - 4) = 0, then

k = 0 or k = 4.

Answered by ShiningSilveR
26
\large\bf{Hey\:mate\:here\:is\:ur\:ans}

Given eq. :

x² + kx + k = 0

If roots are real and equal, then Discriminant = 0

=> b² - 4ac = 0

here, b = k, a = 1, c = k

=> k² - 4.1.k = 0

=> k² - 4k = 0

=> k(k-4) = 0

=> either k = 0 or k - 4 = 0

=> k = 0,4
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