Question

if the roots of X2 + Kx+k=0 real and equal ' what is the value of x ? .( 0) ,(4),(0 or 4),(2),​

Answer 1

Answer:

$x{2}$+kx+k=0

it is given it has real and equal roots

i.e. $b{2}$-4ac=0

   a=1 b=k c= k

 $k{2}$-4(1)(k)=0

k2 -4k =0

k2 =4k

k=$\sqrt4k$

k=2$\sqrt{k$

if k=0

than

k=2$\sqrt{0$

k=2(0)

k=0

Step-by-step explanation: