Question

If the roots of x3 - 7x2 + 14x - 8 = 0 are in G.P, then the roots are​

Answer 1

Answer:

Put x=1

1−7+14−8=0

So x−1 is a factor of given equation

Dividing given equation by (x−1) we get

x

2

−6x+8

So the given equation is

(x−1)(x

2

−6x+8)=0

(x−1)(x−2)(x−4)=0

x=1,2,4