Question

If the rotational kinetic energy of a body is increased by 300% then the percentage increase in its angular momentum will be
1. 600%
2. 150%
3. 100%
4. 1500%

Answer 1

Answer:

(3) 100%

Explanation:

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Answer 2

Concept:

A sort of energy that an item or particle possesses as a result of its mobility is known as kinetic energy. Kinetic energy can be expressed in terms of K = p²/2m

Given:

The rotational kinetic energy is increased by 300%

Find:

We need to determine the percentage increase in the angular momentum of a body.

Solution:

We know, that present kinetic energy = K

New kinetic energy will be given by = K'

It has been given that,

K' = K + 300% K

K' = K + 3K

K' = 4K ----- equation 1

We know that Kinetic energy, K = p²/2m

Therefore, equation 1 becomes-

p'²/2m =  4p²/2m

p'² = 4p²

Taking sq root on both sides

p' = 2p

Therefore, % change in momentum = (p' - p)/p × 100

% change in momentum = (2p - p) / p × 100

% change in momentum = p/p × 100

% change in momentum = 100%

Thus, the correct option is (3). The percentage increase in the angular momentum of a body will be 100%.

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