if the rth term of an A.P IS 5 and the 5th term is r,then find its (r+5)th term.
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Given:- rth term=5
⇒a+(r-1)d=5..............(1)
5th term =1
⇒ a +4d=r......................(2)
put it in equation (1)
(r-4d)+(r-1)=5
⇒ r-4d+rd-d=5
⇒ r+(r -4 -1)d = 5
⇒ d =5-r ÷r-d =1
thus,a= r-4× (-1)=r+4
= r+5th term is a+(r + 5- 1) d
=(r+4) (r+4) (-1)
=(r+4) - ( r+4)
= 0
hence, the answer is 0
⇒a+(r-1)d=5..............(1)
5th term =1
⇒ a +4d=r......................(2)
put it in equation (1)
(r-4d)+(r-1)=5
⇒ r-4d+rd-d=5
⇒ r+(r -4 -1)d = 5
⇒ d =5-r ÷r-d =1
thus,a= r-4× (-1)=r+4
= r+5th term is a+(r + 5- 1) d
=(r+4) (r+4) (-1)
=(r+4) - ( r+4)
= 0
hence, the answer is 0
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