if the same number be added to the numbers 5,11,15 and 31 ,the resulting numbers are in proportion (a/b=c/d). find the number
abelsubin254abel:
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Answered by
136
Heya,
Let the number be x
5+x/11+x = 15+x/31+x
=>(5+x)(31+x) = (11+x)(15+x)
=>153+5x+31x+x^2=165+11x+15x+x^2
(x^2 is deducted from each side)
=>36x+153=26x+165
=>36x-26x=165-153
=>10x=12
=>x=1.2
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Let the number be x
5+x/11+x = 15+x/31+x
=>(5+x)(31+x) = (11+x)(15+x)
=>153+5x+31x+x^2=165+11x+15x+x^2
(x^2 is deducted from each side)
=>36x+153=26x+165
=>36x-26x=165-153
=>10x=12
=>x=1.2
If it helped plz mark Brainliest
Answered by
58
Let the number be x
5+x/11+x=15+x/31+x
(5+x)(31+x)=(11+x)(15+x)
155 +x^2=36x=165+x^2+26x
We deducted x^2from both sides
36x-27x=165-155
10x=10
X=10/10
X=1
Numbers are =
5+1=6
11+1=12
15+1=16
31+1=32
Proportion = 6/12=16/32
1=1
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