Question

If the same number is added to both the numerator and denominator of a fraction 3/5 then the result is 3/4 . Find
the number.​

Answer 1

${\underline{\sf Answer:}}$

${\boxed{\underline{\sf3=Number}}}$

${\underline{\sf solution:}}$

Let the number be $\texttt{x}$

Here we have given that the same number should be added to both numerator and denominator to make it 3/4.

${\underline{\sf According\:to\: question:}}$

3 + x/5 + x = 3/4

(3 + $\texttt{x}$)4 = 3(5 + $\texttt{x}$)

12 + 4$\texttt{x}$ = 15 + 3$\texttt{x}$

4$\texttt{x}$ - 3$\texttt{x}$ = 15 - 12

$\texttt{x}$ = 3

Answer 2

The required number is 3

Given :

If the same number is added to both the numerator and denominator of a fraction 3/5 then the result is 3/4

To find :

The number

Solution :

Step 1 of 2 :

Form the equation to find the number

Let the required number is x

Now it is given that when the number x is added to both the numerator and denominator of a fraction 3/5 then the result is 3/4

By the given condition

$\displaystyle \sf \frac{3 + x}{5 + x} = \frac{3}{4}$

Step 2 of 2 :

Find the number

$\displaystyle \sf \frac{3 + x}{5 + x} = \frac{3}{4}$

$\displaystyle \sf{ \implies }4(3 + x) = 3(5 + x)$

$\displaystyle \sf{ \implies }12 + 4x = 15 + 3x$

$\displaystyle \sf{ \implies }4x - 3x = 15 - 12$

$\displaystyle \sf{ \implies }x = 3$

Hence the required number is 3

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