Question

If the same values of x and y satisfy the following equations , find the value of m :

4 x + 3y = 10 ; x – 2 y = 8 and mx + 5 y =2 .​

Answer 1

❥︎❥︎ANSWER࿐

First find the values of x and y which satisfy the first two equations.

3x + 7y + 5 =0 ---------(1)

4x - 3y - 8 = 0 ----------(2)

multiply eqn(1) with 4 and eqn(2) with 3

4×(3x + 7y + 5) =4×0

⇒12x + 28y + 20 = 0 -------------(3)

3×(4x - 3y - 8) = 3×0

⇒ 12x -9y - 24 = 0 -------------(4)

subtract eqn(4) from eqn(3), we get

12x + 28y + 20 = 0

12x - 9y - 24 = 0

- + +

37y + 44= 0

⇒ y = -44/37.

Answer 2

Given x−y=28,x−3y=0

⇒28+y=3y

⇒2y=28,y=14

Therefore x=42

Now substituting these values in y=mx+5

$\bold {we \: get \: 14=42m+5,m= \: 9 \div 42}$

...@Khushikumari I think u r wrong :(