Question

if the scalar product of two vectors is equal to the magnitude of their vector product,find the angle between them
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Answer 1

When that is the case,the angle between them is 45°

⑵Reason :

Let x= Scalar product of A and B=abcosθ

y=Magnitude of Vector product of A and B=absinθ

,where θ is the smaller angle between A and B

⑶ When x=y,

absinθ =abcosθ

sinθ =cosθ

sinθ/cosθ=1

tanθ=1

θ=45° or θ=225° , 0°≤ θ≤360°

⑷ But the angle between two vectors A and B is defined as the smaller angle between them=45°

Answer 2

非常抱歉，如果您有任何其他疑问，我不知道该问题的答案。非常抱歉，希望您理解