Question

If the second term of an AP is 13 and 5th term is 25 then what is its 7th term

Answer 1

Here is your answer,

a2 = 13
=> a+d = 13 -------------i

a5 = 25
=> a+4d = 25 -------------ii

a7 = ?

Using Elimination method

a+d = 13
a+4d = 25
--------------------
-3d = -12
=> -d = -12/3
=> -d = -4
=> d = 4
--------------------
a+d = 13
=> a = 13-4
=> a = 9

a7 = a+6d
= 9+6x4
= 9+24
= 33


HOPE IT HELPS YOU !!!

Answer 2

2nd term of an AP , a2 = 13

5th term of the A. P., a5 = 25

A2 = a + ( n-1 ) d

13 = a + d

a = 13 - d

A5 = a + ( 5 - 1 ) d

25 = a + 4d

25 = 13 - d + 4d

25 - 13 = 3d

12 / 3 = d.

d = 4.

Putting value of d, a = 13 - 4 = 9.

7th term of the A. P., a 7 = a + ( 7 - 1 ) d

a 7 = 9 + 6 * 4

a 7 = 9 + 24

a 7 = 33.