Math, asked by ronakgaur200, 10 months ago

If the selling price is half, the loss three times. what is the initial loss percentage?

Answers

Answered by venupillai
2

Answer:

Initial loss = 80%

Step-by-step explanation:

Let cost price = CP

Let the initial selling price = ISP

Let initial loss = L

L = CP - ISP ...(i)

Let new selling price = NSP

Let new loss = NL

NL = CP - NSP ...(ii)

Given

NSP = ISP/2 ..(iii)

The new loss is three times the old loss, which means:

NL = 3*L

NL = 3*(CP - ISP)

Using (iii), we get:

NL = 3*(CP - 2*NSP)

Using (ii), we get:

CP - NSP = 3*(CP - 2*NSP)

CP - NSP = 3*CP - 6*NSP

-NSP + 6*NSP = 3*CP - CP

5*NSP = 2*CP

NSP = (2/5)*CP

But, NSP = ISP/2

Thus,

ISP/2 = (2/5)*CP

ISP  = (2/10)*CP

ISP = (1/5)*CP

L = CP - ISP

L = CP - 1/5*CP

L = (4/5)*CP

Loss%  = 100*[(4/5)*CP]/CP

Loss% = 100*(4/5)

Loss% = 80

The initial loss percentage is 80%

Answered by ashish2473
4

Answer:

20%

Step-by-step explanation:

Let cost price and selling price be CP & SP

Initial loss = C.P - S.P = 1-----------(equ-1)

Now if loss becomes 3 times

Then C.P - 1/2 S.P = 3

= 2 C.P - S.P = 6 ---------------(equ-2)

Solving equ-1 & 2, we get

C.P =5 & S.P = 4

C.P - S.P / C.P *100 = 1 / 5 * 100 = 20% (Loss)

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