If the selling price of 18 oranges is equal to the cost price of 16 oranges then what is the profit or loss ? Please write step by step solution.
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Answered by
125
Given, S.P. of 18 oranges = C.P. of 16 oranges
Let the cost price of 16 oranges be Rs x.
∴ Cost price of 1 orange = Rsx/16
Selling price of 18 oranges = Rs x
∴ Selling price of 1 orange = Rsx/18
Loss = Cost price of 1 orange – Selling price of 1 orange
:loss=x/16-x/18
:loss ={9x-8x/144}=x/144
loss%=loss/c.p×100
=x/144//x/16×100=11.1%
Thus, the loss percent is 11.11% approximately.
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Let the cost price of 16 oranges be Rs x.
∴ Cost price of 1 orange = Rsx/16
Selling price of 18 oranges = Rs x
∴ Selling price of 1 orange = Rsx/18
Loss = Cost price of 1 orange – Selling price of 1 orange
:loss=x/16-x/18
:loss ={9x-8x/144}=x/144
loss%=loss/c.p×100
=x/144//x/16×100=11.1%
Thus, the loss percent is 11.11% approximately.
HOPING IT WILL BE HELPFUL TO YOU
MAKE ME BRAINLEST IF YOU COULD DO SO,
AS I WRITEEN STEP BY STEP
Answered by
7
Answer:
Let the selling price of one orange be x
Then the sp of 18 oranges be 18x
So cp of 16 oranges be 18x
cp of 1 orange be 18x/16
Here
CP>SP
So here is loss
Loss=Cp-sp
=(18x/16)-x
=2x/16
Loss percent=(loss/cp)×100 percent
=(2x/16÷18x/16)×100 percent
=(1/9)×100 percent
=11.1 percent
✌️✌️✌️Hope it will help you ✌️✌️✌️
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