Math, asked by rini200, 3 months ago

If the selling price of 18 oranges is equal to the cost price of 16 oranges, find the loss percent.​

Answers

Answered by simrankaurnagi8685
0

Answer:

11.11%

Step-by-step explanation:

SP of 18 oranges = Rs x

SP of one orange = Rs x/18

CP of 16 oranges = Rs y. ( Since x= y)

CP of one orange = Rs y/16

Profit = (SP - CP)/CP

Profit = (x/18 - x/16)/x/16

Profit = - 16/144 = - 1/9

LP = 100/9 = 11•11%

Answered by HeroDhamalastic
0

Answer:

11 1/9%

Step-by-step explanation:

Given that, Selling price of 18 oranges = cost price of 16 oranges

So, let the cost price of 1 orange be Rs x , Selling price of 18 oranges = Rs 16x

Selling price of 1 orange = Rs 16x/18 By using the formula,

Loss = cost price – selling price = x – 16x/18 = 2x/18 = Rs x/9

By using the formula,

Loss % = (loss/cost price) × 100 = (x/9)/x × 100 = 100/9 = 11 1/9 %

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