Question

If the selling price of 18 oranges is equal to the
cost of price of 16 oranges, find the loss percent.

Please answer step by step​

Answer 1

Let the CP of 1 orange be Rs x

Then,

CP of 16 oranges will be 16×x=16x

And

CP of 16 oranges=SP of 18 pens

Hence,

SP of 18 oranges =16x

Then,

SP of 1 orange=16x÷18=

9

8

x

Since, CP>SP, So

Loss=CP−SP.=18x−16x=Rs2x

Loss(%)=

CP

gain

×100

Loss(%)=

18x

2x

×100=11

9

1

%

hence the answer is 1

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Answer 2

Step-by-step explanation:

Let the CP of 1 orange be Rs x

Then,

CP of 16 oranges will be 16×x=16x

And

CP of 16 oranges=SP of 18 pens

Hence,

SP of 18 oranges =16x

Then,

SP of 1 orange=16x÷18=

9

8

x

Since, CP>SP, So

Loss=CP−SP.=18x−16x=Rs2x

Loss(%)=

CP

gain

×100

Loss(%)=

18x

2x

×100=11

9

1

%

hence the answer is 1

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