Question

if the separation between the plates of a parallel plate condenser is increased what will the effect of electric field​

Answer 1

Answer:

When, seperation between the plates of a charged capacitor increases, capacitance decreases. where, V is the potential applied and d is the distance between the plates of capacitor. Case 1: When, battery is removed, charge q remains constant and potential decreases

Answer 2

Explanation:

decrease because

force=kq²/r²

means force is inversely propotional to distance between the plate ---------------------(1)

F=QE

means force is directly propotional to electric field---‐-------------------‐------------------------(2)

from 1 and 2 we get that

Electric field is inversely propotional to distance

HENCE PROVED