Question

If the sequence 11,26,41 ......641 forms an arithmetic progression, then find the middle term in this
sequence.​

Answer 1

Answer:

326

Step-by-step explanation:

a=11

d=26-11=15

an=641

an= a+(n-1)d

641=11+(n-1)15

630=(n-1)15

42=(n-1)

43=n

SO TOTAL TERMS IN THE AP ARE 43

SO MIDDLE TERM= (43+1)/2= 44/2= 22

an= a+(n-1)d

a22=11+(22-1)15

= 11+21×15

=11+315

=326 ANSWER

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