if the series given below are in g.p then what is the value of 'k 3,(k-2),25/12,125/72.... solve
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Answer:
- 3, (k -2), 25/12, 125/72,... forms a G.P.
Note:
For G.P., b = √(ac)
Here, a = 3, b = (k -2) and c = 25/12
=> k - 2 = √(3 × 25/12)
=> k - 2 = 5/2
=> k = 5/2 + 2
=> k = 9/2
Therefore, the value of k is 9/2.
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