if the set a has 3 elements and the Set B equal to 3, 4, 5, then the find number of element in a ×b
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let the total elements of A and B
(A×B)=n(a)*n(b)
where a=3 & b=3
3×3=9
(A×B)=n(a)*n(b)
where a=3 & b=3
3×3=9
Answered by
11
Answer:
HI THERE,
⇨Given, set A has 3 elements and the elements of set B are {3, 4, and 5}.
So, the number of elements in set B = 3
Then, the number of elements in (A × B) = (Number of elements in A) × (Number of elements in B)
= 3 × 3 = 9
Therefore, the number of elements in (A × B) will be 9.
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