Question

if the set I of all integers be the universal set and let A={x:x is a negative integer} be it's subset.find A'​

Answer 1

Answer:

A' = { x ∈ I : x ∉ A }

   = { integers x : x is not a negative integer }

   = { non-negative integers x }

   = { x : x ≥ 0 }

Answer 2

Answer:

A' = {x : x is a non-negative integer}

Step-by-step explanation:

Given:

I = The set of all integers

 = {. . . . -2 , -1 , 0 , 1 , 2 , . . . .}

A = {x : x is a negative integer}

  = {. . . . -2 , -1 }

We need to find A'

We know that A' is the set obtained when set A is subtracted from set I

=> A' = I - A

        =  {. . . . -2 , -1 , 0 , 1 , 2 , . . . .} -  {. . . . -2 , -1 }

        = { 0 , 1 , 2 , . . . .}

        = {x : x is a non-negative integer}

Therefore, A' = {x : x is a non-negative integer}