if the shadow of a vertical pole at a particular time of the day is equal to√3 time it's height, what is the angel of elevation of the source of light at that time?
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Consider the height of tower be h
∴ height of shadow =√3h .
In a triangle ABC,
tan ∠ACB = h / √3h
tan ∠ACB = 1 / √3
∠ACB = 30°. Therefore, angle of elevation is 30°
30° is the answer.
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