Question

If the shortest wavelength of H-atom in Lyman series is 'X' then the longest wavelength in Balmer
series of He+ is​

Answer 1

$\huge{\underline{\underline{\mathbb{\red{Answer:-}}}}}$

longest wavelength(λl) in Balmer series means 3→ 2 transition 

and shortest  wavelengtha(λs) in Lyman series means infinte orbit → 1 transition which is equal to x

According to question  λs=Rh[121−i21]=Rh=x          (  i= infinite )

λl=Rh[221−321]z2=Rh[365]4=Rh95=95x