If the shortest wavelength of hydrogen atom in balmer series is
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Explanation:
Since, we know that for Balmer series,
For shortest wavelength in Balmer series, the spectral series is given by
1/\lambda = R x 1/4
1/\lambda = R/4
\lambda = 4/R
\lambda = 4 / 1.097 x {{10}^{7}}
\lambda = 3.64 x {{10}^{-7}} m
The lines of Balmer series are found in the visible part of the spectrum.
Hope it helps
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