Question

if the shortest wavelength of Lyman series of hydrogen atom is x then the wavelength of the first line of balmer series of hydrogen atom will be​

Answer 1

Answer:

As we know that,

λ

1

=R(

n

1

2

1

−

n

2

2

1

)Z

2

The shortest wavelength in H-atom of Lyman series is from n

1

=1→n

2

=∞.

Given that the shortest wavelength of hydrogen atom in Lyman series is x.

∴

x

1

=R(

1

1

−

∞

1

)1

2

⇒

x

1

=R

The longest wavelength in Paschen series of He

+

ion will be from n

1

=3→n

2

=4.

∴

λ

′

1

=R(

3

2

1

−

4

2

1

)2

2

⇒

λ

′

1

=

x

4

(

9

1

−

16

1

)

⇒

λ

′

1

=

x

4

×(

144

7

)

⇒λ

′

=

28

144x

⇒λ

′

=

7

36x

Hence the correct answer is

7

36x

.

Explanation:

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