if the shortest wavelength of the spectral line of H atom in lyman series is x,then the shortest wavelength of the line in lyman series of He+ is?
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Answer:
x/4
Explanation:
Formula for finding shortest wavelength,
lambda =n²/RZ²
1st case
(lambda)1= 1²/R=1/R=x
for Lyman series, n=1
for Hydrogen, Z=1
2nd case
(lambda)2=1²/R2²
=1/4R
=1/R into 1/4
=x/4
for Lyman, n=1
for Helium,z=2
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