Math, asked by arpitvishu, 5 hours ago

If the side of a cube is doubled then find theratio between the volume of the first cube and thenew cube.​

Answers

Answered by Yuseong
4

Answer:

1 : 8

Step-by-step explanation:

As per the provided information in the given question, we have :

  • There is a cube.
  • Its side is doubled.

We are asked to calculate the ratio between the volume of the first cube and the new cube.

\longrightarrow Let us assume the the side of the first cube as "a". Therefore, the side of the new cube becomes "2a" as its side is doubled of the first cube.

Volume of the first cube :

  \longrightarrow \sf{\quad { Volume_{(Cube)} = (Side)^3 }} \\

Substituting values, side = a.

  \longrightarrow \sf{\quad { Volume_{(Cube)} = (a)^3 }} \\

Writing the cube of its side.

  \longrightarrow \quad { \textbf{\textsf{Volume}}_{\textbf{\textsf{(Cube)}}} = \textbf{\textsf{a}}^\textbf{\textsf{3} }} \\

 \underline{ \qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad} \\

★ Volume of the new cube :

  \longrightarrow \sf{\quad { Volume_{(New \; Cube)} = (Side)^3 }} \\

Substituting values, side = 2a.

  \longrightarrow \sf{\quad { Volume_{(New \; Cube)} = (2a)^3 }} \\

Writing the cube of its side.

  \longrightarrow \quad { \textbf{\textsf{Volume}}_{\textbf{\textsf{(New \; Cube)}}} = \textbf{\textsf{8a}}^\textbf{\textsf{3}} } \\

 \underline{ \qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad} \\

Ratio between their volumes :

  \longrightarrow \sf{\quad { Ratio_{(Volume)} = \dfrac{Volume_{( Cube)} }{Volume_{(New \; Cube)} } }} \\

Substitute the values.

  \longrightarrow \sf{\quad { Ratio_{(Volume)} = \dfrac{a^3 }{8a^3} }} \\

Cubes of a will get cancelled.

  \longrightarrow \sf{\quad { Ratio_{(Volume)} = \dfrac{1 }{8} }} \\

Henceforth, the ratio can be written as,

  \longrightarrow \quad \underline{\boxed { \textbf{\textsf{Ratio}}_{\textbf{\textsf{(Volumes)}}} =\textbf{\textsf{1 : 8 }}}} \\

Therefore,

⠀⠀⠀⠀★ Ratio = 1 : 8

Answered by kalaheoasn
0

Answer:

The ratio is 1:8

Step-by-step explanation:

Let the initial side of the cube= a units

=> The initial volume = (a units)³= a³ unit³

Now,

The side of the cube is doubled = 2(a units)

= 2a units

The new volume is = (2a unit )³

= 8a³ unit³

Therefore,

The ratio of volume of both the cubes is

= a³ : 8a³

= 1 : 8

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